Tentukan koprdinat titik potong 2 garis dgn persamaan 2x-3y+13=0 dan x+2y=4

Kelas 8 Matematika
Bab SPLDV

x + 2y = 4
x = -2y + 4

2x - 3y + 13 = 0
2 (-2y + 4) - 3y + 13 = 0
-4y + 8 - 3y + 13 = 0
-7y = -21
y = 3

x = -2y + 4
x = -2 . 3 + 4
x = -6 + 4
x = -2

Titik potong = (-2, 3)

2x - 3y + 13 = 0
2x - 3y = - 13

x + 2y = 4

2x - 3y = - 13 (× 1)
x + 2y = 4 (× 2)

2x - 3y = - 13
2x + 4y = ...8
--------------------- -
- 7y = - 21
y = - 21/- 7
y = 3

x + 2y = 4
x + 2(3) = 4
x + 6 = 4
x = 4 - 6
x = - 2

maka koordinat titik potong 2 garis itu (-2,3)

Jadi koordinat titik potong 2 garis persamaan itu adalah (-2,3)