²log ( x² - 2x + 1 ) = ²log ( 2x² - 2 )
Matematika
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Pertanyaan
²log ( x² - 2x + 1 ) = ²log ( 2x² - 2 )
1 Jawaban
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1. Jawaban bangilham
²log ( x² - 2x + 1 ) = ²log ( 2x² - 2 )
( x² - 2x + 1 ) = ( 2x² - 2 )
x² + 2x - 3 = 0
(x + 3)(x - 1) = 0
x = - 3 atau x = 1