Matematika

Pertanyaan

(9a^-3 b^-5/3b^2 a^4)^-2

1 Jawaban


  • [tex]( \frac{9 {a}^{ - 3} {b}^{ - 5} }{3 {b}^{2} {a}^{4} })^{ - 2} \\ = ( \frac{3}{ {b}^{7} {a}^{7} } )^{ - 2} \\ = ( \frac{3}{ {b}^{7} {a}^{7} } )^{ - 2} \\ = ( \frac{ {b}^{7 } {a}^{7} }{3} )^{2} \\ = ( \frac{ {a}^{7} {b}^{7} }{3} )^{2} \\ = \frac{ {a}^{14} {b}^{14} }{9 } [/tex]

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