Tolong bantuannya nomor 25 dan 26

25. Sudut ACB = 1/2 × sudut AOB
[tex] \frac{1}{2} \times (180 - sudut \: aod) \\ = \frac{1}{2} \times (180 - 80) \\ = \frac{1}{2} \times 100 \\ = {50}^{o} [/tex]
26. Panjang kawat = keliling × 3
[tex]keliling \: = \frac{sudut \: taman}{ {360}^{o} } \times 2 \times \pi \times r \\ = \frac{120}{360} \times 2 \times \frac{22}{7} \times 21 \\ = \frac{1}{3} \times 2 \times 22 \times 3 \\ = 2 \times 22 \\ = 44 \: {m}^{2} [/tex]
Panjang kawat = 44 × 3 = 132 m