Matematika

Pertanyaan

coba gimana ini bantuin dong buat hari ini kak
coba gimana ini bantuin dong buat hari ini kak

1 Jawaban

  • sisi kiri
    [tex] \left[\begin{array}{cc}6&1\\a&2\end{array}\right] \left[\begin{array}{cc}-1&4\\2&b\end{array}\right] = \left[\begin{array}{cc}-4&24+b\\-a+4&4a+2b\end{array}\right][/tex]
    sisi kanan
    [tex]\left[\begin{array}{cc}2&22\\6&-10\end{array}\right]+ \left[\begin{array}{cc}-6&0\\1&-6\end{array}\right] = \left[\begin{array}{cc}-4&22\\7&-16\end{array}\right][/tex]

    maka
    [tex]\left[\begin{array}{cc}-4&24+b\\-a+4&4a+2b\end{array}\right] = \left[\begin{array}{cc}-4&22\\7&-16\end{array}\right][/tex]
    a= -3
    b= -2
    jadi 3a-5b = 3(-3) -5(-2) = -9 +10 = 1 (A)