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Matematika
nabila12318
Pertanyaan
coba gimana ini bantuin dong buat hari ini kak
1 Jawaban
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1. Jawaban diditsatriyadiox8ng4
sisi kiri
[tex] \left[\begin{array}{cc}6&1\\a&2\end{array}\right] \left[\begin{array}{cc}-1&4\\2&b\end{array}\right] = \left[\begin{array}{cc}-4&24+b\\-a+4&4a+2b\end{array}\right][/tex]
sisi kanan
[tex]\left[\begin{array}{cc}2&22\\6&-10\end{array}\right]+ \left[\begin{array}{cc}-6&0\\1&-6\end{array}\right] = \left[\begin{array}{cc}-4&22\\7&-16\end{array}\right][/tex]
maka
[tex]\left[\begin{array}{cc}-4&24+b\\-a+4&4a+2b\end{array}\right] = \left[\begin{array}{cc}-4&22\\7&-16\end{array}\right][/tex]
a= -3
b= -2
jadi 3a-5b = 3(-3) -5(-2) = -9 +10 = 1 (A)