diketahui fungsi f(x)=2x+1 , g(x)=x²+2 dan h(x)=x+1 . tentukan [ho(gof)](2)

f (x) = 2x +1, g(x) = x^2 + 2 , dan h(x) = x + 1
h o g o f(2)
= h o g { f(x) }
= h o g { f (2) }
= h o g (2.2 + 1)
= h o g ( 5)
= h { g (5) }
= h (5^2 + 2)
= h (27)
= 27 + 1
= 28