hasil dari 2akar 27×akar 32 ÷akar48 [tex] \sqrt[2]{27} \times \sqrt{32} \div \sqrt{48} [/tex]

[tex]2 \sqrt{27} \times\ \sqrt{32} \div \sqrt{48} = 2 \sqrt{3\times9} \times\ \sqrt{2\times16} \div \sqrt{3\times16} \\ = 6 \sqrt{3} \times\ \sqrt{2} \div \sqrt{3} = 6 \sqrt{2} [/tex]
jawaban: D