minta bantuannya dong kak pakai carannya ya.... tolong dijawab ya kak... makasih

RA = 6 ohm
RB = 12 ohm
RC = 15 ohm
IA = 0,5 A

Pararel :
1/Rp = 1/RA + 1/RB + 1/RC
1/Rp = 1/6 + 1/12 + 1/15
1/Rp = 10/60 + 5/60 + 4/60
1/Rp = 19/60
Rp = 60/19 ohm

V = IA × RA
V = 0,5 × 6
V = 3 A

ID = V/Rp
ID = 3/(60/19)
ID = 3 × 19/60
ID = 57/60
ID = 0,95 A

Jadi kuat arus ID adalah 0,95 A (A)