Tolong dong nomor 56

[tex] \sqrt{ { {3} }^{x - 1} } = ( \frac{1}{3} )^{x + 2} \\ = { {3}^{2} }^{(x - 1 {)}^{ \frac{1}{2} ?} } = {(3}^{ - 1} {)}^{x + 2} \\ = {3}^{x - 1} = {3}^{ - x - 2} \\ x - 1 = - x - 2 \\ 2x \: = - 1 \\ x = \frac{ - 1}{2} [/tex]
Jadi jawabannya C ya x nya =-1/2