50 ml larutan HCL 0.1 m dicampur dengan 100 ml larutan NaOH 0.2 m .maka ph larutan tersebut

Mol HCl = 50 x 0,1 = 5 mmol
Mol NaOH = 100 x 0,2 = 20 mmol
HCl + NaOH -> NaCl + H2O
mula: 5. 20. - -
reaksi: 5. 5. 5. 5
sisa: - 15. 5. 5

[NaOH] = 15 mmol/150 mL = 0,1 molar
pOH = - log 0,1 = 1
pH = 13
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