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Pertanyaan

hitunglah pH larutan ch 3 cooh 0,03 m ( ka = 1,2 10 akar -5

1 Jawaban

  • [h+]= ✓kax ma
    =✓ 1,2.10^-5.3.10^-2
    =√3.6x10^-7
    =✓36x10^-8
    =6x10^-4
    pH=-log [h+]
    = -log 6x 10^-4
    =4-log 6

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