(1+3akar2) - (4- akar50)

[tex] = (1 + 3\sqrt{2}) - (4 - \sqrt{50})\\ = 1 + 3\sqrt{2} - 4 + \sqrt{50} \\ = 3\sqrt{2} - 3 + 5\sqrt{2} \\ = 8\sqrt{2} - 3 \\ \therefore (1+3\sqrt{2}) -(4 -\sqrt{50}) = 8\sqrt{2} - 3[/tex]