Buktikan bahwa 1+cos2A per 1-cos2A=cos²A per sin²A

[tex] \frac{1 + \cos2x }{1 - \cos2x } = \frac{ { \cos }^{2} x}{ { \sin }^{2} x} \\ bukti \\ \frac{1 + (2 { \cos }^{2} x - 1)}{1 - (1 - 2 { \sin }^{2} x)} \\ \frac{2 { \cos }^{2} x}{2 { \sin x}^{2} } \\ \frac{ { \cos }^{2}x }{ { \sin }^{2} x} [/tex]
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