Diketahui f(x)=(x+1)(x-1).hitung nilai f¹(-1)

fx= x^2-x+x-1
fx= x^2-1
fx^-1= x^2-1
y= x^2-1
-x^2= -y-1 (dikali minus)
x^2= y+1
[tex]x = + - \sqrt{y + 1} \\ fx = + - \sqrt{x + 1} [/tex]
fx^-1(1)=
[tex] \sqrt{x + 1} = \sqrt{1 + 1} = \sqrt{2} [/tex]

f(x) = (x+1)(x-1) = x² - x + x - 1 = x² - 1 f'(x) = x² - 1 y = x² - 1 y + 1 = x² √y + 1 = Maka, f'(x) = √x+1 f'(1) = √1+1 = √2