Kordinat titik balik grafik fungsi f(x)=2x²-9x+5
Matematika
Riff0777
Pertanyaan
Kordinat titik balik grafik fungsi f(x)=2x²-9x+5
1 Jawaban
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1. Jawaban Anonyme
Kelas 10 Matematika
Bab Fungsi Kuadrat
f(x) = 2x² - 9x + 5
a = 2; b = -9; c = 5
Sumbu simetri
= -b/2a
= - (-9)/(2 . 2)
= 9/4
f(9/4) = 2 . (9/4)² - 9 . 9/4 + 5
f(9/4) = 2 . 81/16 - 81/4 + 5
f(9/4) = 81/8 - 162/8 + 40/8
f(9/4) = -41/8
Koordinat titik balik = (9/4, -41/8)