tolong bantu nomor 5,6

Semoga bermanfaat :-)
5.
[tex] \frac{sudut \: aob}{sudut \: cod} = \frac{panjang \: busur \: ab}{panjang \: busur \: cd} \\ \frac{40}{160} = \frac{panjang \: busur \: ab}{48} \\ \frac{1}{4} = \frac{panjang \: busur \: ab}{48} \\ 4\times panjang \: busur = 1 \times 48 \\ panjang \: busur = \frac{1 \times 48}{4} \\ = \frac{48}{4} \\ = 12 \: cm[/tex]
6.
[tex]3x + 2x + x = {180}^{o} \\ 6x = {180}^{o} \\ x = \frac{180}{6} \\ x = {30}^{o} [/tex]
Besar sudut RPQ = 3x = 3 × 30 = 90 derajat
Besar sudut RQP = 2x = 2 × 30 = 60 derajat
Besar sudut QPR = 180 - 90 - 60= 30 derajat